35v^2+75v-60=0

Solution for 35v^2+75v-60=0 equation:

35v^2+75v-60=0

a = 35; b = 75; c = -60;
Δ = b2-4ac
Δ = 752-4·35·(-60)
Δ = 14025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14025}=\sqrt{25*561}=\sqrt{25}*\sqrt{561}=5\sqrt{561}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(75)-5\sqrt{561}}{2*35}=\frac{-75-5\sqrt{561}}{70}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(75)+5\sqrt{561}}{2*35}=\frac{-75+5\sqrt{561}}{70}
$